Efflex

Efflex – Designer Effects for Flex

12 Responses to “Efflex”

  1. Michael Watts says:
    April 11, 2010 at 3:05 pm

    Hey Tink,
    Everyone here loves you blog and we were wondering if you’d like to crosslink with ours: http://labs.byhook.com/

    Thanks!
    Michael

    Reply
  2. Prika says:
    April 21, 2010 at 10:13 am

    wei tink,

    how are you?
    I have some doubts about the efflex and their implementation through actionscript 3.0.
    Can you help me, please..?

    Thanks a lot for everything.

    TinkWorld.addChild(prika)

    Reply
  3. Prika says:
    April 21, 2010 at 1:13 pm

    I would like to know how can I make efflex’s transitions dynamically.

    I am using a database to store the effects and properties, but I think I can’t use variables in effect’s creation:

    For example:

    (Static)
    var eff1:org.efflex.mx.viewStackEffects.Fade = new org.efflex.mx.viewStackEffects.Fade();

    (Dynamic)

    var effect:String = “org.efflex.mx.viewStackEffects.Fade”;
    var eff1:effect = new effect();

    Any ideia?

    Thanks

    Reply
  4. Tink says:
    April 21, 2010 at 1:32 pm

    I Prika this is possible

    You would need to make sure any classes that you want to use are compiled into your SWF. If all the classes required are not compiled into the SWF, the following will fail…

    var effectClass:Class = getDefinitionByName( org.efflex.mx.viewStackEffects.Fade ) as Class;
    var effect:IEffect = IEffect( new effectClass( param0, param1 ) );

    now you can assign that effect.

    Reply
  5. Prika says:
    April 21, 2010 at 2:05 pm

    Humm.. sorry for the inconvenience, but I don’t understand how I create in runtime.

    ——————————————
    static is working

    var effect:org.efflex.mx.viewStackEffects.Fade = new org.efflex.mx.viewStackEffects.Fade();

    effect.alphato = 0;
    and effect is a type=org.efflex.mx.viewStackEffects.Fade()

    —————————————————————–
    Dynamic is not working

    var eff:String = “org.efflex.mx.viewStackEffects.Fade”;
    var effectClass:Class = getDefinitionByName(eff) as Class;
    var effect:IEffect = IEffect( new effectClass( param0, param1 ) );

    The variable effect is not equal to “org.efflex.mx.viewStackEffects.Fade()”.

    How can I create?

    Reply
  6. Tink says:
    April 21, 2010 at 2:09 pm

    Do you get an error?

    Reply
  7. Prika says:
    April 21, 2010 at 2:21 pm

    I don’t get any error, but I can’t acess the property “alphaTo” (por example) by the class name. Like this:

    effect.alphato = 0;

    var eff:String = “org.efflex.mx.viewStackEffects.Fade”;
    var effectClass:Class = getDefinitionByName(eff) as Class;
    var effect:IEffect = IEffect( new effectClass( param0, param1 ) );

    i would like to make that effect:org.efflex.mx.viewStackEffects.Fade but the effect is IEffect and I don’t know how IEffect works.

    Reply
  8. Tink says:
    April 21, 2010 at 2:37 pm

    You won’t be able to access specific properties as the instance is typed as IEffect. You could type it as a specific effect, but then it wouldn’t be dynamic.

    You should be to set the properties as so

    effect[ "alphaTo" ] = 0;

    This would throw an error if the class didn’t have the property.

    This means that if your switching effects you going to need some kind of switch statement to set the properties (as each effect has diff props), and therefore if you going to have a switch for each diff effect, you might as well just use that switch to create the effect itself instead of using getDefinitionByName.

    Reply
  9. Ward says:
    June 4, 2010 at 7:37 am

    Hi, Tink

    Do you have plan to release CubeAway3DTile? I want to use it in my apps but cannot find where it is. Waiting for your response. Thanks.

    Reply
  10. jiajin says:
    June 29, 2010 at 9:05 am

    Do you have plan to release CubeAway3DTile? I want to use it in my apps but cannot find where it is. Waiting for your response. Thanks.

    I cannot find anywhere it is . I crazy like it.

    Reply

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